Cycle a list from alternating sides

Question

Given a list

a = [0,1,2,3,4,5,6,7,8,9]

how can I get

b = [0,9,1,8,2,7,3,6,4,5]

That is, produce a new lis

Answer 1

Not sure, whether this can be written more compactly, but it is efficient as it only uses iterators / generators

a = [0,1,2,3,4,5,6,7,8,9]

iter1 = iter(a)
iter2 = reversed(a)
b = [item for n, item in enumerate(
        next(iter) for _ in a for iter in (iter1, iter2)
    ) if n < len(a)]