Assigning NULL to a list element in R?

后端 未结 4 1092
囚心锁ツ
囚心锁ツ 2020-12-13 23:18

I found this behaviour odd and wanted more experienced users to share their thoughts and workarounds. On running the code sample below in R:

sampleList <-         


        
4条回答
  •  谎友^
    谎友^ (楼主)
    2020-12-13 23:44

    Good question.

    Check out the R-FAQ:

    In R, if x is a list, then x[i] <- NULL and x[[i]] <- NULL remove the specified elements from x. The first of these is incompatible with S, where it is a no-op. (Note that you can set elements to NULL using x[i] <- list(NULL).)

    consider the following example:

    > t <- list(1,2,3,4)
    > t[[3]] <- NULL          # removing 3'd element (with following shifting)
    > t[2] <- list(NULL)      # setting 2'd element to NULL.
    > t
    [[1]]
    [2] 1
    
    [[2]]
    NULL
    
    [[3]]
    [3] 4
    

    UPDATE:

    As the author of the R Inferno commented, there can be more subtle situations when dealing with NULL. Consider pretty general structure of code:

    # x is some list(), now we want to process it.
    > for (i in 1:n) x[[i]] <- some_function(...)
    

    Now be aware, that if some_function() returns NULL, you maybe will not get what you want: some elements will just disappear. you should rather use lapply function. Take a look at this toy example:

    > initial <- list(1,2,3,4)
    > processed_by_for <- list(0,0,0,0)
    > processed_by_lapply <- list(0,0,0,0)
    > toy_function <- function(x) {if (x%%2==0) return(x) else return(NULL)}
    > for (i in 1:4) processed_by_for[[i]] <- toy_function(initial[[i]])
    > processed_by_lapply <- lapply(initial, toy_function)
    > processed_by_for
      [[1]]
      [1] 0
    
      [[2]]
      [1] 2
    
      [[3]]
      NULL
    
      [[4]]
      [1] 4
    
    > processed_by_lapply
      [[1]]
      NULL
    
      [[2]]
      [1] 2
    
      [[3]]
      NULL
    
      [[4]]
      [1] 4
    

提交回复
热议问题