I saw this question is a programming interview book, here I\'m simplifying the question.
Assume you have an array A of length n, and you ha
@RinRisson has given the only completely correct answer so far! Every other answer has been something that required extra storage — O(n) stack space, or assuming that the permutation P was conveniently stored adjacent to O(n) unused-but-mutable sign bits, or whatever.
Here's RinRisson's correct answer written out in C++. This passes every test I have thrown at it, including an exhaustive test of every possible permutation of length 0 through 11.
Notice that you don't even need the permutation to be materialized; we can treat it as a completely black-box function OldIndex -> NewIndex:
template
void permute(RandomIt first, RandomIt last, const F& p)
{
using IndexType = std::decay_t;
IndexType n = last - first;
for (IndexType i = 0; i + 1 < n; ++i) {
IndexType ind = p(i);
while (ind < i) {
ind = p(ind);
}
using std::swap;
swap(*(first + i), *(first + ind));
}
}
Or slap a more STL-ish interface on top:
template
void permute(RandomIt first, RandomIt last, ForwardIt pfirst, ForwardIt plast)
{
assert(std::distance(first, last) == std::distance(pfirst, plast));
permute(first, last, [&](auto i) { return *std::next(pfirst, i); });
}