Why unique-ptr doesn't check base class to virtual destructible?

Question

Consider this example :

#include 
#include 

struct base
{
    base( int i ): i(i)    {    printf(\"base ctor\\n\"); }
    ~base(         


        

Answer 1

Not all unique_pointers are used polymorphically:

std::unique_ptr p(new int(42));

This would not compile with the restriction you propose. Same with classes:

std::unique_ptr p(new YourClassHere);