How can I transform a Map to a case class in Scala?

Question

If I have a Map[String,String](\"url\" -> \"xxx\", \"title\" -> \"yyy\"), is there an way to generically transform it into a case class Image(url:St

Answer 1

You can transform map to json and then to case class. It's a bit hacky though.

import spray.json._

object MainClass2 extends App {
  val mapData: Map[Any, Any] =
    Map(
      "one" -> "1",
      "two" -> 2,
      "three" -> 12323232123887L,
      "four" -> 4.4,
      "five" -> false
    )

  implicit object AnyJsonFormat extends JsonFormat[Any] {
    def write(x: Any): JsValue = x match {
      case int: Int           => JsNumber(int)
      case long: Long          => JsNumber(long)
      case double: Double        => JsNumber(double)
      case string: String        => JsString(string)
      case boolean: Boolean if boolean  => JsTrue
      case boolean: Boolean if !boolean => JsFalse
    }
    def read(value: JsValue): Any = value match {
      case JsNumber(int) => int.intValue()
      case JsNumber(long) => long.longValue()
      case JsNumber(double) => double.doubleValue()
      case JsString(string) => string
      case JsTrue      => true
      case JsFalse     => false
    }
  }

  import ObjJsonProtocol._
  val json = mapData.toJson
  val result: TestObj = json.convertTo[TestObj]
  println(result)

}

final case class TestObj(one: String, two: Int, three: Long, four: Double, five: Boolean)

object ObjJsonProtocol extends DefaultJsonProtocol {
  implicit val objFormat: RootJsonFormat[TestObj] = jsonFormat5(TestObj)
}

and use this dependency in sbt build:

 "io.spray"          %%   "spray-json"     %   "1.3.3"