Django reset_password_confirm TemplateSyntaxError problem

Question

when I use django.contrib.auth.views.password_reset_confirm without arguments at all it works and I can render the template without any problem, when adding

Answer 1

if you are using app_name in every urls.py

suppose you have an app and in that app in urls.py you have mentioned app_name="accounts" in order to retrieve the page you need to mention two things template_name and success_url inside the PasswordResetView(template_name="accounts/password_reset.html" , success_url= reverse_lazy('accounts:password_reset_sent'))

dont forget to import reverse_lazy from django.urls inside urls.py

so your final code of accounts/urls.py should look like

My app name is landing instead of accounts

from django.urls import path
from . import views
from django.contrib.auth import views as auth_views
from django.urls import reverse_lazy

app_name='landing'

urlpatterns = [
     path('',views.home,name="home"),
     path('terms/',views.terms,name="terms"),
     path('login/',views.loginUser,name="login"),
     path('signup/',views.signupUser,name="signup"),
     path('about/',views.about,name="about"),
     path('logout/',views.logoutUser,name="logout"),

     path('password_reset/',
          auth_views.PasswordResetView.as_view(template_name='landing/password_reset.html',success_url=reverse_lazy('landing:password_reset_done')),
               name="password_reset"),

     path('password_reset_sent/',
          auth_views.PasswordResetDoneView.as_view(template_name='landing/password_reset_sent.html'),
          name="password_reset_done"),

     path('reset///',
          auth_views.PasswordResetConfirmView.as_view(template_name='landing/password_reset_form.html',success_url=reverse_lazy('landing:password_reset_complete')),
          name="password_reset_confirm"),

     path('password_reset_complete/',
          auth_views.PasswordResetCompleteView.as_view(template_name='landing/password_reset_done.html'),
          name="password_reset_complete"),

]

you have to use app_name: before the name of url you have mentioned it is very important