Pretty file size in Ruby?

Question

I\'m trying to make a method that converts an integer that represents bytes to a string with a \'prettied up\' format.

Here\'s my half-working attempt:

Answer 1

@Darshan Computing's solution is only partial here. Since the hash keys are not guaranteed to be ordered this approach will not work reliably. You could fix this by doing something like this inside the to_filesize method,

 conv={
      1024=>'B',
      1024*1024=>'KB',
      ...
 }
 conv.keys.sort.each { |s|
     next if self >= s
     e=conv[s]
     return "#{(self.to_f / (s / 1024)).round(2)}#{e}" if self < s }
 }

This is what I ended up doing for a similar method inside Float,

 class Float
   def to_human
     conv={
       1024=>'B',
       1024*1024=>'KB',
       1024*1024*1024=>'MB',
       1024*1024*1024*1024=>'GB',
       1024*1024*1024*1024*1024=>'TB',
       1024*1024*1024*1024*1024*1024=>'PB',
       1024*1024*1024*1024*1024*1024*1024=>'EB'
     }
     conv.keys.sort.each { |mult|
        next if self >= mult
        suffix=conv[mult]
        return "%.2f %s" % [ self / (mult / 1024), suffix ]
     }
   end
 end