How to generate an array with random values, without using a loop?

Question

How can I generate an array in Perl with 100 random values, without using a loop?

I have to avoid all kind of loops, like \"for\", foreach\", while. This is my exerc

Answer 1

For amusement value:

A method that works on systems where EOL is a single character:

#!/usr/bin/perl

use strict;
use warnings;

$/ = \1;

open 0;
my @r = map rand,<0>;

print "@r\n";

A possibly nondeterministic method that does not use for, while, until:

#!/usr/bin/perl
use strict; use warnings;

my @rand;

NOTLOOP:
push @rand, rand;
sleep 1;
goto NOTLOOP if 100 > time - $^T;

print 0 + @rand, "\n";

Using regular expressions:

#!/usr/bin/perl
use strict; use warnings;

my $s = '-' x 100;
$s =~ s/(-)/rand() . $1/eg;
my @rand = $s=~ m/([^-]+)/g;

Copying and pasting 100 rand invocations by hand is really passé:

#!/usr/bin/perl
use strict; use warnings;

my $s = '(' . 'rand,' x 100 . ')';
my @rand = eval $s;

A file I/O based solution that does not require /dev/random:

#!/usr/bin/perl
use strict; use warnings;

$/ = \1;

my @rand;

seek \*DATA, 0, 0;

NOTLOOP:
scalar ;
push @rand, rand;
goto NOTLOOP if $. < 100;
__DATA__

No reason to use recursion with Perl's goto

#!/usr/bin/perl
use strict; use warnings;
use autodie;

$/ = \1;

open my $F, '<', \( 1 x 100 . 0 );

my @rand or ¬loop;

sub notloop {
    my $t = <$F>;
    $t or return;
    push @rand, rand;
    goto \¬loop;
}

Here is a recursive string eval version:

#!/usr/bin/perl
use strict; use warnings; use autodie;

local $/ = \1;
open my $F, '<', \( 1 x 100 . 0 );

my @rand;

eval <<'NOLOOP'
my $self = (caller(0))[6];
<$F> or die;
push @rand, rand;
eval $self;
NOLOOP
;

Of course, all of these actually do contain loops, but they do not use the keywords you were barred from using.

NB: This question has brought out the wacko in me, but I must admit it is amusing.