NOT(~) vs NEGATION(!)

Question

#include 

using namespace std;
int main(int argc, char *argv[]) 
{
   int i=-5;
   while(~(i))
   {
      cout<         


        

Answer 1

You are correct about i == -1 being the exit condition: your loop is equivalent to

int i=-5;
while(i != -1)
{
    cout<

When written this way, it should be clear why -1 is not printed the value is first printed, and only then incremented, that's why -2 is the last value that you print.

The ! operator, on the other hand, will produce 1 only when it is given a zero. That's why the loop would print -1 when the ! operator is used in the loop condition.