Why aren't exceptions in C++ checked by the compiler?

Question

C++ provides a syntax for checked exceptions, for example:

void G() throw(Exception);
void f() throw();

However, the Visual C++ compiler do

Answer 1

Because the standard says so. The exception declaration doesn't mean that no other exception will be thrown. It means that if an undeclared exception is thrown, there will be called a special global function called unexpected(), which by default terminates the program. Generally declaring exceptions in functions is discouraged (maybe except for empty exception list) as the standard behaviour is not very helpful.