using sql count in a case statement

Question

I have a table and i need to present the output in the following fashion.

tb_a:

col1  |  reg_id | rsp_ind 

Count of rows with rsp_ind = 0

Answer 1

Depending on you flavor of SQL, you can also imply the else statement in your aggregate counts.

For example, here's a simple table Grades:

| Letters |
|---------|
| A       |
| A       |
| B       |
| C       |

We can test out each Aggregate counter syntax like this (Interactive Demo in SQL Fiddle):

SELECT
    COUNT(CASE WHEN Letter = 'A' THEN 1 END)           AS [Count - End],
    COUNT(CASE WHEN Letter = 'A' THEN 1 ELSE NULL END) AS [Count - Else Null],
    COUNT(CASE WHEN Letter = 'A' THEN 1 ELSE 0 END)    AS [Count - Else Zero],
    SUM(CASE WHEN Letter = 'A' THEN 1 END)             AS [Sum - End],
    SUM(CASE WHEN Letter = 'A' THEN 1 ELSE NULL END)   AS [Sum - Else Null],
    SUM(CASE WHEN Letter = 'A' THEN 1 ELSE 0 END)      AS [Sum - Else Zero]
FROM Grades

And here are the results (unpivoted for readability):

|    Description    | Counts |
|-------------------|--------|
| Count - End       |    2   |
| Count - Else Null |    2   |
| Count - Else Zero |    4   | *Note: Will include count of zero values
| Sum - End         |    2   |
| Sum - Else Null   |    2   |
| Sum - Else Zero   |    2   |

Which lines up with the docs for Aggregate Functions in SQL

Docs for COUNT:

COUNT(*) - returns the number of items in a group. This includes NULL values and duplicates.
COUNT(ALL expression) - evaluates expression for each row in a group, and returns the number of nonnull values.
COUNT(DISTINCT expression) - evaluates expression for each row in a group, and returns the number of unique, nonnull values.

Docs for SUM:

ALL - Applies the aggregate function to all values. ALL is the default.
DISTINCT - Specifies that SUM return the sum of unique values.