For a JavaScript library I\'m implementing, I need to clone an element which has exactly the same applied style than the original one. Although I\'ve gained
After looking at a couple of good solutions across the WEB, I decided to combine all the best aspects of each and come up with this.
I left my solution in plain super fast Javascript, so that everybody can translate to their latest and great JS flavour of the month.
Representing the vanilla from manilla.....
* @problem: Sometimes .cloneNode(true) doesn't copy the styles and your are left
* with everything copied but no styling applied to the clonedNode (it looks plain / ugly). Solution:
*
* @solution: call synchronizeCssStyles to copy styles from source (src) element to
* destination (dest) element.
*
* @author: Luigi D'Amico (www.8bitplatoon.com)
*
*/
function synchronizeCssStyles(src, destination, recursively) {
// if recursively = true, then we assume the src dom structure and destination dom structure are identical (ie: cloneNode was used)
// window.getComputedStyle vs document.defaultView.getComputedStyle
// @TBD: also check for compatibility on IE/Edge
destination.style.cssText = document.defaultView.getComputedStyle(src, "").cssText;
if (recursively) {
var vSrcElements = src.getElementsByTagName("*");
var vDstElements = destination.getElementsByTagName("*");
for (var i = vSrcElements.length; i--;) {
var vSrcElement = vSrcElements[i];
var vDstElement = vDstElements[i];
// console.log(i + " >> " + vSrcElement + " :: " + vDstElement);
vDstElement.style.cssText = document.defaultView.getComputedStyle(vSrcElement, "").cssText;
}
}
}