Get the newest directory in bash to a variables

Question

I would like to find the newest sub directory in a directory and save the result to variable in bash.

Something like this:

ls -t /backups | head -1 &         


        

Answer 1

Your "something like this" was almost a hit:

BACKUPDIR=$(ls -t ./backups | head -1)

Combining what you wrote with what I have learned solved my problem too. Thank you for rising this question.

Note: I run the line above from GitBash within Windows environment in file called ./something.bash.