cc1plus: warning: command line option “-Wstrict-prototypes” is valid for Ada/C/ObjC but not for C++

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日久生厌 2020-12-13 12:40

I am building a C++ extension for use in Python. I am seeing this warning being generated during the compilation process - when a type:

python setup.py build         


        
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  •  攒了一身酷
    2020-12-13 13:10

    I can answer part of the question, why you're getting the message.

    Something in your build process is invoking gcc on a C++ source file with the option -Wstrict-prototypes. For C and Objective-C, this causes the compiler to warn about old-style function declarations that don't declare the types of arguments.

    For C++, this option doesn't make sense; such declarations aren't even allowed by the language (prototypes are mandatory).

    (I don't know why the message mentions Ada; -Wstrict-prototypes makes even less sense for Ada than for C++. It's not a huge deal, but I've submitted this bug report, marked as RESOLVED/FIXED as of 2015-12-06.)

    The solution should be to remove the -Wstrict-prototypes option from the invocation of gcc. But since you're not invoking gcc directly, it's difficult to know how to do that.

    I was able to reproduce the warning using your setup.py, after manually creating a dummy example_wrap.cxx file:

    % python setup.py build_ext -i
    running build_ext
    building '_foolib' extension
    gcc -pthread -fno-strict-aliasing -DNDEBUG -g -fwrapv -O2 -Wall -Wstrict-prototypes -fPIC -I/usr/include/python2.7 -c example_wrap.cxx -o build/temp.linux-i686-2.7/example_wrap.o
    cc1plus: warning: command line option "-Wstrict-prototypes" is valid for Ada/C/ObjC but not for C++
    ...
    

    So it's probably a minor bug in Python's build_ext.

    But since it's only a warning, not a fatal error, I'd say you can safely ignore it. gcc warns about the meaningless option, but then it just ignores it.

    EDIT:

    Looking through the Python-2.7.2 sources, this section of configure.in might be the culprit:

    case $GCC in
    yes)
        if test "$CC" != 'g++' ; then
            STRICT_PROTO="-Wstrict-prototypes"
        fi
    

    (I'm assuming that's invoked when using build_ext.)

    It turns on the -Wstrict-prototypes option only if the compiler is not being invoked as g++ -- but in your case it's using the gcc command to compile C++ source code. And in Lib/distutils/command/build_ext.py, build_extension() doesn't pay attention to the source file language when invoking self.compiler.compile(), only when invoking self.compiler.link_shared_object(). (Which seems odd; for compilers other than gcc, you wouldn't necessarily be able to use the same command to compile C and C++ -- and it makes more sense to use the g++ command anyway, even if you're not linking.)

    UPDATE: A Python bug report was submitted: https://bugs.python.org/issue9031, and closed as a duplicate of this one: https://bugs.python.org/issue1222585, which is still open as I write this.

    But as I said, it's only a warning and you can probably safely ignore it. Perhaps the Python maintainers can use the above information to fix the problem in a future release.

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