Rfc2898 / PBKDF2 with SHA256 as digest in c#

Question

I want to use Rfc2898 in c# to derive a key. I also need to use SHA256 as Digest for Rfc2898. I found the class Rfc2898DeriveBytes, but it uses SHA-1 and I don\

Answer 1

See Bruno Garcia's answer.

Carsten: Please accept that answer rather than this one.

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At the time I started this answer, Rfc2898DeriveBytes was not configurable to use a different hash function. In the meantime, though, it has been improved; see Bruno Garcia's answer. The following function can be used to generate a hashed version of a user-provided password to store in a database for authentication purposes.

For users of older .NET frameworks, this is still useful:

// NOTE: The iteration count should
// be as high as possible without causing
// unreasonable delay.  Note also that the password
// and salt are byte arrays, not strings.  After use,
// the password and salt should be cleared (with Array.Clear)

public static byte[] PBKDF2Sha256GetBytes(int dklen, byte[] password, byte[] salt, int iterationCount){
    using(var hmac=new System.Security.Cryptography.HMACSHA256(password)){
        int hashLength=hmac.HashSize/8;
        if((hmac.HashSize&7)!=0)
            hashLength++;
        int keyLength=dklen/hashLength;
        if((long)dklen>(0xFFFFFFFFL*hashLength) || dklen<0)
            throw new ArgumentOutOfRangeException("dklen");
        if(dklen%hashLength!=0)
            keyLength++;
        byte[] extendedkey=new byte[salt.Length+4];
        Buffer.BlockCopy(salt,0,extendedkey,0,salt.Length);
        using(var ms=new System.IO.MemoryStream()){
            for(int i=0;i>24)&0xFF);
                extendedkey[salt.Length+1]=(byte)(((i+1)>>16)&0xFF);
                extendedkey[salt.Length+2]=(byte)(((i+1)>>8)&0xFF);
                extendedkey[salt.Length+3]=(byte)(((i+1))&0xFF);
                byte[] u=hmac.ComputeHash(extendedkey);
                Array.Clear(extendedkey,salt.Length,4);
                byte[] f=u;
                for(int j=1;j