How to extract URL from Link in Google Sheets using a formula?

Question

I have copied from a website a series of hyperlinks and pasted them in a google sheet. The values show up as linked text, not hyperlink formulas, and are still linked correc

Answer 1

Ryan Tarpine's Example helped a lot. Thanks!

With the code below, you can replace all embedded links by standard HYPERLINK formulas within a selected Range. Please note, that the Advanced Sheets Service must be activated.

function embeddedURLsToHyperlink() {
  var spreadsheet = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = spreadsheet.getActiveSheet();
  var rows = sheet.getActiveRange().getValues();
  var z = sheet.getActiveRange().getRowIndex();
  var s = sheet.getActiveRange().getColumn();

  for (var r = 0; r < rows.length; r++) {
    var row = rows[r];
    for (var c = 0; c < row.length; c++) {
      var val = row[c];
      if (val) {
        var targetRange = sheet.getRange(r+z, c+s).getA1Notation();
        var result = Sheets.Spreadsheets.get(spreadsheet.getId(), {
          ranges: sheet.getName() + "!" + targetRange,
          fields: 'sheets.data.rowData.values'
        });
        if (result.sheets[0].data[0].rowData[0].values[0].hyperlink) {
          var url = result.sheets[0].data[0].rowData[0].values[0].hyperlink;
          var text = result.sheets[0].data[0].rowData[0].values[0].effectiveValue.stringValue;
          sheet.getRange(r + z, c + s).setFormula('=HYPERLINK("' + url + '","' + text + '")');
        }
      }
    }
  }
}

I you want to process the full sheet, replace lines 4-6 by the following code:

var rows = sheet.getDataRange().getValues();
var z = 1;
var s = 1;