JavaScript isPrototypeOf vs instanceof usage

Question

Suppose we have the following:

function Super() {
      // init code
}

function Sub() {
      Super.call(this);
      // other init code
}

Sub.prototype =          


        

Answer 1

According to this MDN Ref:

isPrototypeOf() differs from the instanceof operator. In the expression object instanceof AFunction, the object prototype chain is checked against AFunction.prototype, not against AFunction itself.