Best way to create a “run-once” time delayed function in C#

Question

I am trying to create a function that takes in an Action and a Timeout, and executes the Action after the Timeout. The function is to be non-blocking. The function must be

Answer 1

I don't know which version of C# you are using. But I think you could accomplish this by using the Task library. It would then look something like that.

public class PauseAndExecuter
{
    public async Task Execute(Action action, int timeoutInMilliseconds)
    {
        await Task.Delay(timeoutInMilliseconds);
        action();
    }
}