I was given the following problem in an interview:
Given a staircase with N steps, you can go up with 1 or 2 steps each time. Output all possible way
You can generalize your recursive function to also take already made moves.
void steps(n, alreadyTakenSteps) {
if (n == 0) {
print already taken steps
}
if (n >= 1) {
steps(n - 1, alreadyTakenSteps.append(1));
}
if (n >= 2) {
steps(n - 2, alreadyTakenSteps.append(2));
}
}
It's not really the code, more of a pseudocode, but it should give you an idea.