multiple parallel async calls with await

Question

As far as I know, when runtime comes across the statement below it wraps the rest of the function as a callback to the method which is invoked asynchronously (someCall

Answer 1

The simplest way is probably to do this:

var taskA = someCall();
var taskB = someOtherCall();
await taskA;
await taskB;

This is especially nice if you want the result values:

var result = await taskA + await taskB;

so you don't need to do taskA.Result.

TaskEx.WhenAll might be faster than two awaits after each other. i don't know since I haven't done performance investigation on that, but unless you see a problem I think the two consecutive awaits reads better, especially if you ewant the result values.