Parallel map in haskell

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既然无缘
既然无缘 2020-12-13 06:49

Is there some substitute of map which evaluates the list in parallel? I don\'t need it to be lazy.

Something like: pmap :: (a -> b) -> [a] -

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  •  暖寄归人
    2020-12-13 07:33

    Yes, see the parallel package:

    ls `using` parList rdeepseq
    

    will evaluate each element of the list in parallel via the rdeepseq strategy. Note the use of parListChunk with a good chunk value might give better performance if your elements are too cheap to get a benefit evaluating each one in parallel (because it saves on sparking for each element).

    EDIT: Based on your question I feel I should explain why this is an answer. It's because Haskell is lazy! Consider the statement

    let bs = map expensiveFunction as
    

    Nothing has been evaluated. You've just created a thunk that maps expensiveFunction. So how do we evaluate it in parallel?

    let bs = map expensiveFunction as
        cs = bs `using` parList rdeepseq
    

    Now don't use the bs list in your future computations, instead use the cs list. IOW, you don't need a parallel map, you can use the regular (lazy) maps and a parallel evaulation strategy.

    EDIT: And if you look around enough you'll see the parMap function that does what I showed here but wrapped into one helper function.

    In response to your comment, does the below code not work for you? it works for me.

    import Control.Parallel.Strategies
    
    func as =
            let bs = map (+1) as
                cs = bs `using` parList rdeepseq
            in cs
    

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