Could not find an overload for '/' that accepts the supplied arguments

前端 未结 2 1281
北海茫月
北海茫月 2020-12-13 06:09
// Playground - noun: a place where people can play


func getAverage(numbers: Int...) -> Double{
    var total = 0
    var average:Double = 0

    for number in          


        
2条回答
  •  独厮守ぢ
    2020-12-13 07:01

    There are no such implicit conversions in Swift, so you'll have to explicitly convert that yourself:

    average = Double(total) / Double(numbers.count)
    

    From The Swift Programming Language: “Values are never implicitly converted to another type.” (Section: A Swift Tour)

    But you're now using Swift, not Objective-C, so try to think in a more functional oriented way. Your function can be written like this:

    func getAverage(numbers: Int...) -> Double {
        let total = numbers.reduce(0, combine: {$0 + $1})
        return Double(total) / Double(numbers.count)
    }
    

    reduce takes a first parameter as an initial value for an accumulator variable, then applies the combine function to the accumulator variable and each element in the array. Here, we pass an anonymous function that uses $0 and $1 to denote the first and second parameters it gets passed and adds them up.

    Even more concisely, you can write this: numbers.reduce(0, +).

    Note how type inference does a nice job of still finding out that total is an Int.

提交回复
热议问题