How to extract a value from a string using regex and a shell?

Question

I am in shell and I have this string: 12 BBQ ,45 rofl, 89 lol

Using the regexp: \\d+ (?=rofl), I want 45 as a result.

Answer 1

You can use rextract to extract using a regular expression and reformat the result.

Example:

[$] echo "12 BBQ ,45 rofl, 89 lol" | ./rextract '[,]([\d]+) rofl' '${1}'
45