I want to convert binary data to hexadecimal, just that, no fancy formatting and all. hexdump
seems too clever, and it \"overformats\" for me. I want to take x
These three commands will print the same (0102030405060708090a0b0c):
n=12
echo "$a" | xxd -l "$n" -p
echo "$a" | od -N "$n" -An -tx1 | tr -d " \n" ; echo
echo "$a" | hexdump -n "$n" -e '/1 "%02x"'; echo
Given that n=12
and $a
is the byte values from 1 to 26:
a="$(printf '%b' "$(printf '\\0%o' {1..26})")"
That could be used to get $n
random byte values in each program:
xxd -l "$n" -p /dev/urandom
od -vN "$n" -An -tx1 /dev/urandom | tr -d " \n" ; echo
hexdump -vn "$n" -e '/1 "%02x"' /dev/urandom ; echo