Unzipping directory structure with python

Question

I have a zip file which contains the following directory structure:

dir1\\dir2\\dir3a
dir1\\dir2\\dir3b

I\'m trying to unzip it and maintai

Answer 1

There's a very easy way if you're using Python 2.6: the extractall method.

However, since the zipfile module is implemented completely in Python without any C extensions, you can probably copy it out of a 2.6 installation and use it with an older version of Python; you may find this easier than having to reimplement the functionality yourself. However, the function itself is quite short:

def extractall(self, path=None, members=None, pwd=None):
    """Extract all members from the archive to the current working
       directory. `path' specifies a different directory to extract to.
       `members' is optional and must be a subset of the list returned
       by namelist().
    """
    if members is None:
        members = self.namelist()

    for zipinfo in members:
        self.extract(zipinfo, path, pwd)