Django ListView - Form to filter and sort

Question

My Goal

• A site that list all my Updates (model) in a table
• Dont display all models at once (pagination - maybe 10 per page)

Answer 1

You don't need post. Pass the filter value and order_by in the url for example:

.../update/list/?filter=filter-val&orderby=order-val

and get the filter and orderby in the get_queryset like:

class MyView(ListView):
    model = Update
    template_name = "updates/update.html"
    paginate_by = 10

    def get_queryset(self):
        filter_val = self.request.GET.get('filter', 'give-default-value')
        order = self.request.GET.get('orderby', 'give-default-value')
        new_context = Update.objects.filter(
            state=filter_val,
        ).order_by(order)
        return new_context

    def get_context_data(self, **kwargs):
        context = super(MyView, self).get_context_data(**kwargs)
        context['filter'] = self.request.GET.get('filter', 'give-default-value')
        context['orderby'] = self.request.GET.get('orderby', 'give-default-value')
        return context

Make sure you give proper default value to filter and orderby

Example form (you can modify this to your need):

    
Filter: 
    
order_by: