Regex to match a digit two or four times

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日久生厌
日久生厌 2020-12-12 21:45

It\'s a simple question about regular expressions, but I\'m not finding the answer.

I want to determine whether a number appears in sequence exactly two

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  •  没有蜡笔的小新
    2020-12-12 22:05

    There's no specific syntax for that, but there are lots of ways to do it:

    (?:\d{4}|\d{2})    <-- alternation: four digits if possible, else just two
    \d{2}(?:\d{2})?    <-- two digits, plus two more if possible
    (?:\d{2}){1,2}     <-- two digits, times one or two
    

    So, for example, to match strings consisting of one or more letters A–Z followed by either two or four digits, you might write ^[A-Z]+(?:\d{4}|\d{2})$; and to match a comma-separated list of two-or-four-digit numbers, you might write ^((?:\d{4},|\d{2},)*(?:\d{4}|\d{2})$ or ^(?:\d{2}(?:\d{2})?,)*\d{2}(?:\d{2})$.

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