SwiftUI - Is there a popViewController equivalent in SwiftUI?

Question

I was playing around with SwiftUI and want to be able to come back to the previous view when tapping a button, the same we use popViewController inside a

Answer 1

EDIT: This answer over here is better than mine, but both work: SwiftUI dismiss modal

What you really want (or should want) is a modal presentation, which several people have mentioned here. If you go that path, you definitely will need to be able to programmatically dismiss the modal, and Erica Sadun has a great example of how to do that here: https://ericasadun.com/2019/06/16/swiftui-modal-presentation/

Given the difference between declarative coding and imperative coding, the solution there may be non-obvious (toggling a bool to false to dismiss the modal, for example), but it makes sense if your model state is the source of truth, rather than the state of the UI itself.

Here's my quick take on Erica's example, using a binding passed into the TestModal so that it can dismiss itself without having to be a member of the ContentView itself (as Erica's is, for simplicity).

struct TestModal: View {
    @State var isPresented: Binding

    var body: some View {
        Button(action: { self.isPresented.value = false }, label: { Text("Done") })
    }
}

struct ContentView : View {
    @State var modalPresented = false

    var body: some View {
        NavigationView {
            Text("Hello World")
            .navigationBarTitle(Text("View"))
            .navigationBarItems(trailing:
                Button(action: { self.modalPresented = true }) { Text("Show Modal") })
        }
        .presentation(self.modalPresented ? Modal(TestModal(isPresented: $modalPresented)) {
            self.modalPresented.toggle()
        } : nil)
    }
}