ruby super keyword

Question

From what I understand, super keyword invokes a method with the same name as the current method in the superclass of the current class. Below in the autol

Answer 1

Use Pry

Insert a binding.pry call right before you use super, and then invoke show-source -s (-s means superclass) to show the superclass method and find out where it's defined:

class A
  def hello
    puts "hi"
  end
end

class B < A
  def hello
    binding.pry
    super
  end
end

b = B.new
b.hello

From: (pry) @ line 7 B#hello:

     7: def hello
 =>  8:   binding.pry
     9:   super
    10: end

[1] (pry) #: 0> show-source -s

From: (pry) @ line 2:
Number of lines: 3
Owner: A   # <--see owner here (i.e superclass)
Visibility: public

def hello
  puts "hi"
end
[2] (pry) #: 0>