I am trying to use gulp-requirejs to build a demo project. I expect result to be a single file with all js dependencies and template included. Here is my gulpfile.js
My solution works like this:
./client/js/main.js:
require.config({
paths: {
jquery: "../vendor/jquery/dist/jquery",
...
},
shim: {
...
}
});
define(["jquery"], function($) {
console.log($);
});
./gulpfile.js:
var gulp = require('gulp'),
....
amdOptimize = require("amd-optimize"),
concat = require('gulp-concat'),
...
gulp.task('scripts', function(cb) {
var js = gulp.src(path.scripts + '.js')
.pipe(cached('scripts'))
.pipe(jshint())
.pipe(jshint.reporter('default'))
.pipe(remember('scripts'))
.pipe(amdOptimize("main",
{
name: "main",
configFile: "./client/js/main.js",
baseUrl: './client/js'
}
))
.pipe(concat('main.js'));
.pipe(gulp.dest(path.destScripts));
}
...
This part was important:
configFile: "./client/js/main.js",
baseUrl: './client/js'
This allowed me to keep my configuration in one place. Otherwise I was having to duplicate my paths and shims into gulpfile.js.