Convert ConfigParser.items('') to dictionary

Question

How can I convert the result of a ConfigParser.items(\'section\') to a dictionary to format a string like here:

import ConfigParser

config = ConfigParser.Co         


        

Answer 1

Another alternative would be:

config.ini

[DEFAULT]
potato=3

[foo]
foor_property=y
potato=4


[bar]
bar_property=y

parser.py

import configparser
from typing import Dict


def to_dict(config: configparser.ConfigParser) -> Dict[str, Dict[str, str]]:
    """
    function converts a ConfigParser structure into a nested dict
    Each section name is a first level key in the the dict, and the key values of the section
    becomes the dict in the second level
    {
        'section_name': {
            'key': 'value'
        }
    }
    :param config:  the ConfigParser with the file already loaded
    :return: a nested dict
    """
    return {section_name: dict(config[section_name]) for section_name in config.sections()}

main.py

import configparser

from parser import to_dict


def main():
    config = configparser.ConfigParser()
    # By default section names are parsed to lower case, optionxform = str sets to no conversion.
    # For more information: https://docs.python.org/3/library/configparser.html#configparser-objects
    # config.optionxform = str
    config.read('config.ini')
    print(f'Config read: {to_dict(config)}')
    print(f'Defaults read: {config.defaults()}')


if __name__ == '__main__':
    main()