Why is “int i = 2147483647 + 1;” OK, but “byte b = 127 + 1;” is not compilable?

Question

Why is int i = 2147483647 + 1; OK, but byte b = 127 + 1; is not compilable?

Answer 1

As an evidence to @MByD:

The following code compiles:

byte c = (byte)(127 + 1);

Because although expression (127 + 1) is int and beyond the scope off byte type the result is casted to byte. This expression produces -128.