Stripping linux shared libraries

Question

We\'ve recently been asked to ship a Linux version of one of our libraries, previously we\'ve developed under Linux and shipped for Windows where deploying libraries is gene

Answer 1

So the solution we have for now is as follows:

test.cpp

#include 
#include 
#include 

struct private_struct
{
    float f;
};

float private_function(float f)
{
    return std::abs(f);
}

void other_private_function()
{
    std::vector f(1);
}

extern "C" void __attribute__ ((visibility ("default"))) public_function2()
{
    other_private_function();
}

extern "C" float __attribute__ ((visibility ("default"))) public_function1(float f)
{
    return private_function(f);
}

exports.version

LIBTEST 
{
global:
    public*;
local:
    *;
};

compiled with

g++ -shared test.cpp -o libtest.so -fvisibility=hidden -fvisibility-inlines-hidden -s -Wl,--version-script=exports.version

gives

00000000 A LIBTEST
         w _Jv_RegisterClasses
         U _Unwind_Resume
         U std::__throw_bad_alloc()
         U operator delete(void*)
         U operator new(unsigned int)
         w __cxa_finalize
         w __gmon_start__
         U __gxx_personality_v0
000005db T public_function1
00000676 T public_function2

Which is fairly close to what we're looking for. There are a few gotchas though:

• We have to ensure we don't use the "exported" prefix (in this simple example "public", but obviously something more useful in our case) in the internal code.
• Many symbol names still end up in the string table, which appears to be down to RTTI, -fno-rtti makes them go away in my simple tests, but is a rather nuclear solution.

I'm happy to accept any better solutions anyone comes up with!