Converting html to text with Python

Question

I am trying to convert an html block to text using Python.

Input:

Answer 1

I was in need of a way of doing this on a client's system without having to download additional libraries. I never found a good solution, so I created my own. Feel free to use this if you like.

import urllib 

def html2text(strText):
    str1 = strText
    int2 = str1.lower().find("0:
       str1 = str1[int2:]
    int2 = str1.lower().find("")
    if int2>0:
       str1 = str1[:int2]
    list1 = ['
',  '', 'span>', 'li>', '' ]
    list2 = [chr(13), chr(13), chr(9), chr(13), chr(13),  chr(13), chr(13), chr(13)]
    bolFlag1 = True
    bolFlag2 = True
    strReturn = ""
    for int1 in range(len(str1)):
      str2 = str1[int1]
      for int2 in range(len(list1)):
        if str1[int1:int1+len(list1[int2])].lower() == list1[int2]:
           strReturn = strReturn + list2[int2]
      if str1[int1:int1+7].lower() == '' or str1[int1:int1+11].lower() == '':
         bolFlag1 = True
      if str2 == '<':
         bolFlag2 = False
      if bolFlag1 and bolFlag2 and (ord(str2) != 10) :
        strReturn = strReturn + str2
      if str2 == '>':
         bolFlag2 = True
      if bolFlag1 and bolFlag2:
        strReturn = strReturn.replace(chr(32)+chr(13), chr(13))
        strReturn = strReturn.replace(chr(9)+chr(13), chr(13))
        strReturn = strReturn.replace(chr(13)+chr(32), chr(13))
        strReturn = strReturn.replace(chr(13)+chr(9), chr(13))
        strReturn = strReturn.replace(chr(13)+chr(13), chr(13))
    strReturn = strReturn.replace(chr(13), '\n')
    return strReturn


url = "http://www.theguardian.com/world/2014/sep/25/us-air-strikes-islamic-state-oil-isis"    
html = urllib.urlopen(url).read()    
print html2text(html)