Confusion about array initialization in C

Question

In C language, if initialize an array like this:

int a[5] = {1,2};

then all the elements of the array that are not initialized explicitly w

Answer 1

The assignment a[2]= 1 is an expression that has the value 1, and you essentially wrote int a[5]= { 1 }; (with the side effect that a[2] is assigned 1 as well).