Confusion about array initialization in C

Question

In C language, if initialize an array like this:

int a[5] = {1,2};

then all the elements of the array that are not initialized explicitly w

Answer 1

My Understanding is a[2]=1 returns value 1 so code becomes

int a[5]={a[2]=1} --> int a[5]={1}

int a[5]={1} assign value for a[0]=1

Hence it print 1 for a[0]

For example

char str[10]={‘H’,‘a’,‘i’};


char str[0] = ‘H’;
char str[1] = ‘a’;
char str[2] = ‘i;