How sendmsg works?

Question

As you know sendmsg has this declaration:

int sendmsg(int s, const struct msghdr *msg, int flags);

and msghdr

Answer 1

The manpage speaks of a message (singular) and multiple elements (plural):

For send() and sendto(), the message is found in buf and has length len. For sendmsg(), the message is pointed to by the elements of the array msg.msg_iov. The sendmsg() call also allows sending ancillary data (also known as control information).

For a stream socket, it wouldn't matter either way. Any data you send will just end up as one long stream of data on the other side.

For datagram or message sockets, I can see why a bit more clarity would be helpful. But it appears that you send just one datagram or message with a single sndmsg call; not one per buffer element.

I actually went digging in the Linux source code out of curiosity and to get a better feeling about this answer. It looks like send, and sendto are just wrappers for sendmsg in Linux, that build the struct msghdr for you. And in fact, the UDP sendmsg implementation makes room for one UDP header per sendmsg call.

If performance is what you're worried about, it doesn't look like you'll benefit from sendmsg if you pass in just a single iovec. If you're concatenating buffers in user-space, though, this could potentially win you some.

It's a bit similar to writev, with the added benefit that you can specify a destination address for use with connectionless sockets like UDP. You can also add ancillary data, if you're into that sort of thing. (Commonly used to send file descriptors across UNIX domain sockets.)