virtual function call from base class

Question

Say we have:

Class Base
{   
    virtual void f(){g();};
    virtual void g(){//Do some Base related code;}
};

Class Derived : public Base
{   
    virtual         


        

Answer 1

pBase is a pointer to a base. pBase = new Derived returns a pointer to a Derived - Derived is-a Base.

So pBase = new Derived is valid.

pBase references a Base, so it will look at Derived as if it were a Base.

pBase->f() will call Derive::f();

Then we see in the code that:

Derive::f() --> Base::f() --> g() - but which g??

Well, it calls Derive::g() because that is the g that pBase "points" to.

Answer: Derive::g()