virtual function call from base class

Question

Say we have:

Class Base
{   
    virtual void f(){g();};
    virtual void g(){//Do some Base related code;}
};

Class Derived : public Base
{   
    virtual         


        

Answer 1

It is the Derived::g, unless you call g in Base's constructor. Because Base constructor is called before Derived object is constructed, Derived::g can not logically be called cause it might manipulate variables that has not been constructed yet, so Base::g will be called.