What Regex would capture everything from ' mark to the end of a line?

Question

I have a text file that denotes remarks with a single \'.

Some lines have two quotes but I need to get everything from the first instance of a \

Answer 1

This will capture everything up to the ' in backreference 1 - and everything after the ' in backreference 2. You may need to escape the apostrophes though depending on language (\')

/^([^']*)'?(.*)$/

Quick modification: if the line doesn't have an ' - backreference 1 should still catch the whole line.

^ - start of string
([^']*) - capture any number of not ' characters
'? - match the ' 0 or 1 time
(.*) - capture any number of characters
$ - end of string