Constructing simple Scala case classes from Strings, strictly without boiler-plate

Question

I seek succinct code to initialize simple Scala case classes from Strings (e.g. a csv line):

case class Person(name: String, age: Double)
case class Book(tit         


        

Answer 1

object Creator {
  def create[T: ClassTag](params: String): T = {
    val ctor = implicitly[ClassTag[T]].runtimeClass.getConstructors.head
    val types = ctor.getParameterTypes

    val paramsArray = params.split(",").map(_.trim)

    val paramsWithTypes = paramsArray zip types

    val parameters = paramsWithTypes.map {
      case (param, clas) =>
        clas.getName match {
          case "int" => param.toInt.asInstanceOf[Object] // needed only for AnyVal types
          case "double" => param.toDouble.asInstanceOf[Object] // needed only for AnyVal types
          case _ =>
            val paramConstructor = clas.getConstructor(param.getClass)
            paramConstructor.newInstance(param).asInstanceOf[Object]
        }

    }

    val r = ctor.newInstance(parameters: _*)
    r.asInstanceOf[T]
  }
}