0.1 float is greater than 0.1 double. I expected it to be false [duplicate]

Answer 1

The number 0.1 will be rounded to the closest floating-point representation with the given precision. This approximation might be either greater than or less than 0.1, so without looking at the actual values, you can't predict whether the single precision or double precision approximation is greater.

Here's what the double precision value gets rounded to (using a Python interpreter):

>>> "%.55f" % 0.1
'0.1000000000000000055511151231257827021181583404541015625'

And here's the single precision value:

>>> "%.55f" % numpy.float32("0.1")
'0.1000000014901161193847656250000000000000000000000000000'

So you can see that the single precision approximation is greater.