Why does a return in `finally` override `try`?

Question

How does a return statement inside a try/catch block work?

function example() {
    try {
        return true;
    }
    finally {
        return false;
             


        

Answer 1

The finally block rewrites try block return (figuratively speaking).

Just wanted to point out, that if you return something from finally, then it will be returned from the function. But if in finally there is no 'return' word - it will be returned the value from try block;

function example() {
    try {
        return true;
    }
    finally {
       console.log('finally')
    }
}
console.log(example());
// -> finally
// -> true

So -finally- return rewrites the return of -try- return.