Given an array A of N integers we draw N discs in a 2D plane, such that i-th disc has center in (0,i) and a radius
A Python answer
from bisect import bisect_right
def number_of_disc_intersections(li):
pairs = 0
# treat as a series of intervals on the y axis at x=0
intervals = sorted( [(i-li[i], i+li[i]) for i in range(len(li))] )
# do this by creating a list of start points of each interval
starts = [i[0] for i in intervals]
for i in range(len(starts)):
# find the index of the rightmost value less than or equal to the interval-end
count = bisect_right(starts, intervals[i][1])
# subtract current position to exclude previous matches, and subtract self
count -= (i+1)
pairs += count
if pairs > 10000000:
return -1
return pairs