What's the best way to inverse sort in scala?

Question

What is the best way to do an inverse sort in scala? I imagine the following is somewhat slow.

list.sortBy(_.size).reverse

Is there a conv

Answer 1

this is my code ;)

val wordCounts = logData.flatMap(line => line.split(" "))
                        .map(word => (word, 1))
                        .reduceByKey((a, b) => a + b)

wordCounts.sortBy(- _._2).collect()