How to drop all tables from a database with one SQL query?

Question

I don\'t want to type all tables\' name to drop all of them. Is it possible with one query?

Answer 1

I Know this question is very old but every Time i need this code .. by the way if you have tables and views and Functions and PROCEDURES you can delete it all by this Script .. so why i post this Script ?? because if u delete all tables you will need to delete all views and if you have Functions and PROCEDURES you need to delete it too
i Hope it will help someone

DECLARE @sql NVARCHAR(max)=''

 SELECT @sql += ' Drop table ' + QUOTENAME(TABLE_SCHEMA) + '.'+ QUOTENAME(TABLE_NAME) 
+ '; '
FROM   INFORMATION_SCHEMA.TABLES
WHERE  TABLE_TYPE = 'BASE TABLE'

Exec Sp_executesql @sql


 DECLARE @sql VARCHAR(MAX) = ''
    , @crlf VARCHAR(2) = CHAR(13) + CHAR(10) ;

 SELECT @sql = @sql + 'DROP VIEW ' + QUOTENAME(SCHEMA_NAME(schema_id)) + '.' + 
 QUOTENAME(v.name) +';' + @crlf
 FROM   sys.views v

 PRINT @sql;
 EXEC(@sql);

 declare @procName varchar(500)
 declare cur cursor 

 for select [name] from sys.objects where type = 'p'
 open cur
 fetch next from cur into @procName
 while @@fetch_status = 0
 begin
  exec('drop procedure [' + @procName + ']')
fetch next from cur into @procName
 end
  close cur
  deallocate cur

  Declare @sql NVARCHAR(MAX) = N'';

    SELECT @sql = @sql + N' DROP FUNCTION ' 
               + QUOTENAME(SCHEMA_NAME(schema_id)) 
               + N'.' + QUOTENAME(name)
    FROM sys.objects
  WHERE type_desc LIKE '%FUNCTION%';

   Exec sp_executesql @sql
  GO