Is there a way to perform “if” in python's lambda

Question

In python 2.6, I want to do:

f = lambda x: if x==2 print x else raise Exception()
f(2) #should print \"2\"
f(3) #should throw an exception
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Answer 1

the solution for the given scenerio is:

f = lambda x : x if x == 2 else print("number is not 2")
f(30)  # number is not 2
f(2)   #2