Is there a way to perform “if” in python's lambda

Question

In python 2.6, I want to do:

f = lambda x: if x==2 print x else raise Exception()
f(2) #should print \"2\"
f(3) #should throw an exception
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Answer 1

I think this is what you were looking for

>>> f = lambda x : print(x) if x==2 else print("ERROR")
>>> f(23)
ERROR
>>> f(2)
2
>>>