Is there a way to perform “if” in python's lambda

Question

In python 2.6, I want to do:

f = lambda x: if x==2 print x else raise Exception()
f(2) #should print \"2\"
f(3) #should throw an exception
<         


        

Answer 1

Try it:

is_even = lambda x: True if x % 2 == 0 else False
print(is_even(10))
print(is_even(11))

Out:

True
False