Miscalculation of array size inside a function

Question

The following C program:

int doStuff(int afm[]);

int main(){
    int afm1[9] = {1,2,3,4,5,6,7,8,9}; //size=9

    int afmLength = sizeof(afm1)/sizeof(int);
         


        

Answer 1

Adding to David Heffernan's answer (which is correct), you should have another parameter which would be the array length passed onto your doStuff method.